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ERRATUM - At the computation for utilisation factor would be (1car/6mins) / (1car/10mins) = 5/3 or 1.6667. This is a ... Refer to the figure shown. Given: L1 = 15m h2 = 10m w = 20KN/m L2 = 20m h3 = 5m P = 80KN L3 = 9m h1 = 8m H = 10KN A. Please refer my following Playlists , Links are given: 1. Theory of Machines or Kinematics of Machines play list ...
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