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Last Updated: October 19, 2026
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Topics: Arrays | DFS Time Complexity = O(2 ^ n) T(n) = a + 2 * T(n - 1) T(n) = a + 2a + 4a + ... + 2^n * a + T(0) * 2 ^ n = a * 2^(n+1) ... This video is a solution to Leet code If you find this video helpful, please '' or ''. This is really helpful for the channel and also motivates me to do more of ... In this video, I have solved and explained the correct approach to solve the Time Complexity : O(n) because all indexes are being visited only once Space Complexity : O(n) visited array Nov 29th - November LeetCoding Challenge